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Hi Could someone confirm the STRING REPLACEMENT behaviour with REGEX please ?

U

It is possible to find a REGEX within a string (works perfectly) but I think that it doesn't work with the replacement option.

Just to give an example, I try to replace the first letter of words with its uppercase. 

john wayne should become John Wayne

 

The find Regex is ([a-z])([a-z]{0,}) to split the first letters from the others in 2 blocks

According to regex101 website, the substitution should be \U$1\L$2 (\U$$1\L$$2 for AA because of the $ specificity)

The result is not what expected >> UjLohn UwLayne U and L caracters are displayed instead of the first block uppercase transformation

 

Any idea ?

I can make it diffently of course but this is probably the best way i can think about

 

Thx in advance

Stéphane

    3 replies

    B

    Hi @Stéphane Sévos​ ,

     

    Split Input String based on space Delimeter and use list loop to iterate all items try to extract substring and regex as below

     

    imageimageimageRegards,

    Bhargavi

    U
    • User007031
    • Author
    • Cadet | Tier 2
    • 2 replies
    • March 3, 2022

    Thx for your help

     

    I did smthg quite similar based on split and extract

     

    I notice you use a regex tool. Is this an extra package from the bot store ?

     

    According to you, is the original string replace action not fully compatible with regex options (find or substitutions) ?

     

    best rgds

    S.

    B
    1 person likes this
    • B
      baso
    B

    Hi @Stéphane Sévos​ 

     

    * Please download Regex tools package from BOT store.

    *I think with single string replace (regex )won't work for your requirement

     

    Regards,

    Bhargavi

    Reply


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