Question

Hi Could someone confirm the STRING REPLACEMENT behaviour with REGEX please ?

It is possible to find a REGEX within a string (works perfectly) but I think that it doesn't work with the replacement option.

Just to give an example, I try to replace the first letter of words with its uppercase.

john wayne should become John Wayne

The find Regex is (ba-z])(]a-z]{0,}) to split the first letters from the others in 2 blocks

According to regex101 website, the substitution should be \U$1\L$2 (\U$$1\L$$2 for AA because of the $ specificity)

The result is not what expected >> UjLohn UwLayne U and L caracters are displayed instead of the first block uppercase transformation

Any idea ?

I can make it diffently of course but this is probably the best way i can think about

Thx in advance

Stéphane

Split Input String based on space Delimeter and use list loop to iterate all items try to extract substring and regex as below

Regards,

Bhargavi

Thx for your help

I did smthg quite similar based on split and extract

I notice you use a regex tool. Is this an extra package from the bot store ?

According to you, is the original string replace action not fully compatible with regex options (find or substitutions) ?

best rgds

S.

* Please download Regex tools package from BOT store.

*I think with single string replace (regex )won't work for your requirement

Regards,

Bhargavi

Sign up