Hi Could someone confirm the STRING REPLACEMENT behaviour with REGEX please ?

It is possible to find a REGEX within a string (works perfectly) but I think that it doesn't work with the replacement option.

Just to give an example, I try to replace the first letter of words with its uppercase.

john wayne should become John Wayne

The find Regex is (ba-z])(]a-z]{0,}) to split the first letters from the others in 2 blocks

According to regex101 website, the substitution should be \U$1\L$2 (\U$$1\L$$2 for AA because of the $ specificity)

The result is not what expected >> UjLohn UwLayne U and L caracters are displayed instead of the first block uppercase transformation

Any idea ?

I can make it diffently of course but this is probably the best way i can think about

Thx in advance

Stéphane

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Split Input String based on space Delimeter and use list loop to iterate all items try to extract substring and regex as below

Regards,

Bhargavi

Thx for your help

I did smthg quite similar based on split and extract

I notice you use a regex tool. Is this an extra package from the bot store ?

According to you, is the original string replace action not fully compatible with regex options (find or substitutions) ?

best rgds

S.

* Please download Regex tools package from BOT store.

*I think with single string replace (regex )won't work for your requirement

Regards,

Bhargavi

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